Daikin FBQ100D_RZQSG100L9V [19/52] Installation
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Daikin FBQ100D_RZQSG100L9V [19/52] Installation

Daikin FBQ100D_RZQSG100L9V [19/52] Installation
6Installation
Installerreferenceguide
19
RZQG71~140L_V1+Y1+RZQSG100~140L_V1+Y1
Splitsystemairconditioners
4P3855221–2014.08
Typical workflow – Completely recharging refrigerant typically
consistsofthefollowingstages:
1 Determininghowmuchrefrigeranttocharge.
2 Chargingrefrigerant.
3 Fillinginthefluorinatedgreenhousegaseslabel,andfixingitto
theinsideoftheoutdoorunit.
6.6.2 Precautionswhenchargingrefrigerant
INFORMATION
Also read the precautions and requirements in the
followingchapters:
▪ Generalsafetyprecautions
▪ Preparation
6.6.3 Definitions:L1~L7,H1,H2
Pair
(a)
H1
L1
Twin
(a)
H1
H2
L1
L2
L3
Triple
(a)
L2
L3
L4
H1
H2
L1
Doubletwin
(a)
H1
H2
L1
L2
L3
L4
L5
L6
L7
(a) Assumethatthelongestlineintheillustrationcorresponds
withtheactuallongestpipe,andthehighestunitinthe
illustrationcorrespondswiththeactualhighestunit.
L1 Mainpiping
L2~L7 Branchpiping
H1 Heightdifferencebetweenthehighestindoorunitandthe
outdoorunit
H2 Heightdifferencebetweenthehighestandthelowest
indoorunit
Refrigerantbranchkit
6.6.4 Todeterminetheadditionalrefrigerant
amount
Todetermineifaddingadditionalrefrigerantisnecessary
If Then
(L1+L2+L3+L4+L5+L6+L7)≤
chargelesslength
Chargelesslength=
▪ 10m(sizedown)
▪ 30m(standard)
▪ 15m(sizeup)
Youdonothavetoadd
additionalrefrigerant.
(L1+L2+L3+L4+L5+L6+L7)>
chargelesslength
Youmustaddadditional
refrigerant.
Forfutureservicing,encirclethe
selectedamountinthetables
below.
INFORMATION
Pipinglengthisthelargestonewaylengthofliquidpiping.
Todeterminetheadditionalrefrigerantamount(Rinkg)(in
caseofpair)
L1 (m)
L1(standard): 30~40m 40~50m 50~60m
(a)
60~75m
(a)
L1(sizeup): 15~20m 20~25m 25~30m
(a)
30~35m
(a)
R: 0.5kg 1.0kg 1.5kg 2.0kg
(a) OnlyforRZQG100~140.
Todeterminetheadditionalrefrigerantamount(Rinkg)(in
caseoftwin,tripleanddoubletwin)
1 DetermineG1andG2.
G1(m) Totallengthof<x>liquidpiping
x=Ø9.5mm(standard)
x=Ø12.7mm(sizeup)
G2(m) TotallengthofØ6.4mmliquidpiping
2 DetermineR1andR2.
If Then
G1>30m
(a)
Usethetablebelowtodetermine
R1(length=G1−30m)
(a)
andR2
(length=G2).
G1≤30m
(a)
(andG1+G2>30m)
(a)
R1=0.0kg.
Usethetablebelowtodetermine
R2(length=G1+G2−30m)
(a)
.
(a) Incaseofsizeup:Replace30mby15m.
Incaseofstandardliquidpipesize:
Length
0~10m 10~20m 20~30m
(a)
30~45m
(a)
R1: 0.5kg 1.0kg 1.5kg 2.0kg
R2: 0.3kg 0.6kg 0.9kg 1.2kg
Incaseofsizeupliquidpipesize:
Length
0~5m 5~10m 10~15m
(a)
15~20m
(a)
R1,R2: 0.5kg 1.0kg 1.5kg 2.0kg
(a) OnlyforRZQG100~140.
3 Determinetheadditionalrefrigerantamount:R=R1+R2.
Examples
Layout Additionalrefrigerantamount(R)
Case:Twin,standardliquidpipesize
1 G1 TotalØ9.5=>G1=35m
G2 TotalØ6.4=>G2=7+5=12m
2 Case:G1>30m
R1 Length=G1−30m=5m
=>R1=0.5kg
R2 Length=G2=12m
=>R2=0.6kg
3 R R=R1+R2=0.5+0.6=1.1kg

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